Solve the following : (i) \( \tan ^{-1} \frac{x-1}{x+1}+\tan ^{-1} \frac{2 x-1}{2 x+1}=\tan ^{-1} \frac{23}{36} \)

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AshwinKumar · Answer 1 · 2025-02-05T05:55:23+0000

We have, \(tan^{-1} \frac{x-1}{x+1} + tan^{-1} \frac{2x-1}{2x+1} = tan^{-1} \frac{23}{36}\)

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