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Find the value of so that the points (−3, 12), (7, 6) and (, ) are collinear.

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Points are A(-3, 12), B(7, 6) and C(x, 9) are Collinear. Then:

\(\left(x_1=-3, y_1=12\right),\left(x_2=7, y_2=6\right) \text { and }\left(x_3=x, y_3=9\right)\)   

It is given that points A, B and C are Collinear. therefore,  

\(x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)=0 \)  

\(-3(6-9)+7(9-12)+x(12-6)=0 \)  

\(-3(-3)+7(-3)+x(6)=0 \)  

\(+9-21+6 x=0 \)  

-12 + 6x = 0  

6x = 12  

\( x=\frac{12}{6}\)  

x = 2 

Therefore, when x = 2, the given points are Collinear.

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