(a) The graph is one of force vs ∆x so the slope of this graph is the spring constant. Slope = 200N/m
(b) Since there is no friction, energy is conserved and the decrease in kinetic energy will be equal to the gain in spring potential
|∆K| = Usp(f) = ½k∆x2 = ½(200)(0.1)2 = 1J
Note: This is the same as the area under the line since the area would be the work done by the conservative spring force and the work done by a conservative force is equal to the amount of energy transferred.
(c) Using energy conservation.
Ki = Usp(f)
1/2mvo2 = 1J
1/2(5)vo2 = 1
vo = 0.63m/s