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For a diatomic gas, if \(\gamma_{1}=\left(\frac{\mathrm{Cp}}{\mathrm{Cv}}\right)\) for rigid molecules and \(\gamma_{2}=\left(\frac{C p}{C v}\right)\) for another diatomic molecules, but also having vibrational modes. Then, which one of the following options is correct?
(Cp and Cv are specific heats of the gas at constant pressure and volume)

(1) \(\gamma_{2}>\gamma_{1}\)

(2) \(\gamma_{2}=\gamma_{1}\)

(3) \(2 \gamma_{2}=\gamma_{1}\)

(4) \(\gamma_{2}<\gamma_{1}\)

1 Answer

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Best answer

Correct option is : (4) \(\gamma_{2}<\gamma_{1}\) 

\(\gamma=\frac{2}{\mathrm{f}}+1\)

without vibration : \(\mathrm{f}=5: \gamma_{1}=1.4\)

without vibration : \(\mathrm{f}=7: \gamma_{2}=1.14\)

\(\therefore\ \gamma_{2}<\gamma_{1}\)

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