Question

During "S" estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is ______ %.

(Given molar mass in \(g \ mol^{–1}\) of Ba : 137, S : 32, O : 16)

Answer 1

Answer is : 40 

Millimoles of \(\mathrm{BaSO}_{4}=\frac{466}{233}=2 \mathrm{m} \mathrm{~mol}\) 

\( \% \mathrm{~S}=\frac{\frac{466}{233} \times 32}{160} \times 100=40 \%\)