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In \(I(m, n)=\int_{0}^{1} x^{m-1}(1-x)^{n-1} d x, m, n>0,\) then \(\mathrm{I}(9,14)+\mathrm{I}(10,13)\) is

(1) I(9, 1)

(2) I(19, 27)

(3) I(1, 13)

(4) I(9, 13)
 

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Best answer

Correct option is (4) I(9, 13) 

\(I(m, m)=\int_{0}^{1} x^{m-1}(1-x)^{n-1} d x\)

Let \(x=\sin ^{2} \theta \quad d x=2 \sin \theta \cos \theta d \theta\)

\(I(m, n)=2 \int_{0}^{\pi / 2}(\sin \theta)^{2 m-1}(\cos \theta)^{2 n-1} d \theta\)

\(I(9,14)+I(10,13)=2 \int_{0}^{\pi / 2}(\sin \theta)^{17}(\cos \theta)^{27} d \theta\)

\(+2 \int_{0}^{\pi / 2}(\sin \theta)^{19}(\cos \theta)^{25} \mathrm{~d} \theta\)

\(=2 \int_{0}^{\pi / 2}(\sin \theta)^{17}(\cos \theta)^{25} d \theta\)

= I(9, 13)

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