Correct option is (2) 4
Consider \(\frac{1}{\sqrt{\mathrm{x}}}=\alpha \quad \mathrm{x}>0\)
\(\left(9 \alpha^{2}-9 \alpha+2\right)\left(2 \alpha^{2}-7 \alpha+3\right)=0\)
\((3 \alpha-2)(3 \alpha-1)(\alpha-3)(2 \alpha-1)=0\)
\(\alpha=\frac{1}{3}, \frac{1}{2}, \frac{2}{3}, 3\)
\(\mathrm{x}=9,4, \frac{9}{4}, \frac{1}{9}\)
So, no. of solutions = 4