For reaction

The correct order of set of reagents for the above conversion is :
(1) \(\mathrm{Br}_{2} \mid \mathrm{FeBr}_{3}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}\)
(2) \(\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Ac}_{2} \mathrm{O}, \mathrm{Br}_{2}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}\)
(3) \(\mathrm{Ac}_{2} \mathrm{O}, \mathrm{Br}_{2}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}\)
(4) \(\mathrm{Ac}_{2} \mathrm{O}_{,} \mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Br}_{2}, \mathrm{NaOH}\)