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The correct order of set of reagents for the above conversion is :

(1) \(\mathrm{Br}_{2} \mid \mathrm{FeBr}_{3}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}\)

(2) \(\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Ac}_{2} \mathrm{O}, \mathrm{Br}_{2}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}\)

(3) \(\mathrm{Ac}_{2} \mathrm{O}, \mathrm{Br}_{2}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}\)

(4) \(\mathrm{Ac}_{2} \mathrm{O}_{,} \mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Br}_{2}, \mathrm{NaOH}\)

1 Answer

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Correct option is : (2) \(\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Ac}_{2} \mathrm{O}, \mathrm{Br}_{2}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}\) 

The correct order of set 

Correct sequence of reagents

\(H_2SO_4, Ac_2O, Br_2, H_2O(\Delta ), NaOH\)

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