Question

The molarity of a \(70 \%\) (mass/mass) aqueous solution of a monobasic acid (X) is _____ M(Nearest integer)

[Given : Density of aqueous solution of (X) is \(1.25 \mathrm{~g} \mathrm{~mL}^{-1}\)

Molar mass of the acid is \(70 \mathrm{~g} \mathrm{~mol}^{-1}\)]

Answer 1

Answer is : 125

Assuming 100 gm solution contain 70 gm solute.

Volume of 100 gm solution will be \(\frac{100}{1.25} \mathrm{ml}\). 

Molarity \(=\frac{70 / 70}{100 / 1.25} \times 1000=12.5\) or \(125 \times 10^{-1}\)