Arrange the following in increasing order of solubility product : Ca(OH)2, AgBr, PbS, HgS (1) PbS < HgS < Ca(OH)2 < AgBr

Question

Arrange the following in increasing order of solubility product :

\(\mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{AgBr}, \mathrm{PbS}, \mathrm{HgS}\)

(1) \(\mathrm{PbS}<\mathrm{HgS}<\mathrm{Ca}(\mathrm{OH})_{2}<\mathrm{AgBr}\)

(2) \(\mathrm{HgS}<\mathrm{PbS}<\mathrm{AgBr}<\mathrm{Ca}(\mathrm{OH})_{2}\)

(3) \(\mathrm{Ca}(\mathrm{OH})_{2}<\mathrm{AgBr}<\mathrm{HgS}<\mathrm{PbS}\)

(4) \(\mathrm{HgS}<\mathrm{AgBr}<\mathrm{PbS}<\mathrm{Ca}(\mathrm{OH})_{2}\)

Answer 1

Correct option is : (2) \(\mathrm{HgS}<\mathrm{PbS}<\mathrm{AgBr}<\mathrm{Ca}(\mathrm{OH})_{2}\) 

Based on the Ksp values and salt analysis cation identification, we can say that order of Ksp value is:

\(\mathrm{HgS}<\mathrm{PbS}<\mathrm{AgBr}<\mathrm{Ca}(\mathrm{OH})_{2}\) 

Ksp values

\(\mathrm{HgS} \rightarrow 4 \times 10^{-53}\) 

\(\mathrm{PbS} \rightarrow 8 \times 10^{-28}\) 

 \(\mathrm{AgBr} \rightarrow 5 \times 10^{-13}\) 

\(\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow 5.5 \times 10^{-6}\)