Answer is: 8
\(L=m v_{0} R=m \sqrt{\frac{G M}{R}} R=m \sqrt{G M R}\)
here M is mass of star
\(\frac{L_{B}}{L_{A}}=\frac{m_{B}}{m_{A}} \sqrt{\frac{\mathrm{R}_{B}}{\mathrm{R}_{A}}}\)
\(=4 \sqrt{2} \sqrt{\frac{2}{1}}\)
\(\frac{\mathrm{L}_{\mathrm{B}}}{\mathrm{L}_{\mathrm{A}}}=8\)