Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
83 views
in Limit, continuity and differentiability by (25 points)
edited by

\( \lim _{x \rightarrow 0} \frac{(1-\cos (1-\cos x))}{\sin ^{4} x} \)

Please log in or register to answer this question.

2 Answers

0 votes
by (18.5k points)

We have

lim(x→0) ((1 – cos(1 – cos x))/x4)

lim(x→0) ((1 – cos(1 – cos x))/x^4)

0 votes
by (15 points)

\({\lim\limits_{x \to 0} {(1-cos(1-cosx))\over x^4} } \)

\({\lim\limits_{x \to 0} {(1-cos(1-cosx))\over x^4} } *{(1-cosx)^2\over(1-cosx)^2}\)

\(\lim\limits_{x \to 0} {(1-cos(1-cosx))\over(1-cosx)^2}*{(1-cosx)^2\over (x^2)^2} \)

\(= {1 \over 2} * {1 \over 4} = {1 \over 8}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...