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If we want to obtain a virtual and magnified image of an object by using a concave mirror of focal length 18 cm, where should the object be placed? Use mirror formula to determine the object distance for an image of magnification +2 produced by this mirror to justify your answer.

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To obtain a virtual and magnified image of an object by using a concave mirror we should place the object between pole (P) and focus (F) on the principal axis.

The object should be placed at a distance less than 18 cm from the front of mirror.

Now,  \(m=-\frac{v}{u}=+2\)

\(v=-2u\)

As, \(f=-18cm\)

Using mirror formula

\(\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\)

\(\frac{1}{-18}=\frac{1}{-2u}+\frac{1}{u}\)

\(\frac {1}{-18}=\frac{1}{2u}\)

\(u=-9cm\)

The object should be place at 9 cm in front of the mirror, which is between the pole and the focal point to obtain an image of magnification +2.

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