Question

A Dihybrid cross is done between two parent pea plants (pure line) who differ in two pairs of contrasting traits: 

Seed colour and seed shape.

In the \(F_2\) generation the number of phenotypes and genotypes will be:

(A) phenotypes = 4; genotypes = 16

(B) phenotypes = 9; genotypes = 14

(C) phenotypes = 4; genotypes = 8

(D) phenotypes = 4; genotypes = 9

Answer 1

Correct option is: (D) phenotypes = 4; genotypes = 9 

In a dihybrid cross, between two parent pea plant who differ in two pairs of contrasting characters will be, phenotypes = 4 and Genotypes = 9

Cross between seed colour and seed shape

Total phenotypes = 4

The Genotypic ratio

\(1:2:1:2:4:2:1:2:1\)  

Total genotypes = 9.