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in Physics by (43.7k points)

What is the dimensional formula of  \(\frac{1}{\mu_0 \epsilon_0}\) (where \(\mu_0\) is permeability and \(\epsilon_0\) is permittivity of free space).

(1) \(LT^{-1}\)

(2) \(L^2 T^{-2}\)

(3) \(MLT^{-1}\)

(4) \(ML^2 T^{-2}\)

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1 Answer

+1 vote
by (43.3k points)

Correct option is:  (2) \(L^2 T^{-2}\)

\(\frac{1}{\sqrt{\mu_0 \epsilon_0}}=C\)

\(\frac{1}{\mu_0 \epsilon_0} = C^2\)

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