Question

Statement-I : \(O^{2-}\) and \(H^+\) are projected in a magnetic field perpendicular to the field with same speed. The radius of curvature of \(O^{2-}\) will be less than H+ . 

Statement-II : \(e^-\)and \(p^+\) are projected in a magnetic field perpendicular to the field with same speed. The radius of curvature of \(e^-\) will be more the proton. 

(1) Statement-I is correct, statement-II is incorrect 

(2) Both statement-I and statement-II are correct 

(3) Both statement-I and statement-II are incorrect 

(4) Statement-I is incorrect, statement-II is correct

Answer 1

Correct option is: (3) Both statement-I and statement-II are incorrect 

\(r = \frac{Vm}{Bq}\)

\(r_{O^{2-}} > r_{H^+}\)

\(r_{p^{+}} > r_{e^{-}}\)