Question

500 mg of organic compound gives 220 mg of CO₂. Find mass % of carbon atoms present in organic compound.

Answer 1

Answer is : (12)

\(\text{Number of moles of} \ CO_2 = \frac{220\times 10^{-3}}{44} = 5 \times 10^{-3} \ \text{mol}\)

\(\therefore n_{CO_{2}} = n_{c} = 5 \times 10^{-3} \ \text{mol}\)

\(\therefore\) Mass of carbon = 5 × 10^–3 × 12 = 60 × 10^–3 g

\(\therefore \text{Mass % of C-atoms} = \frac{60\times 10^{-3}}{500 \times 10^{-3}} \times 100 \% = 12 \%\)