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If the length of E.Coli DNA is 1.36 mm, Calculate the number of base pairs it contains.

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If the length of E.Coli DNA is 1.36 mm, Calculate the number of base pairs it contains.

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The distance between two adjacent bp = 0.34 × 10–9 m length = Total no. of bp × distance between two bp. 

No. of bp. = 1.36 × 10–3/0.34× 10–9 = 4 × 106 bp

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