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in Mathematics by (44.2k points)

The sum of series \({ }^{2} C_{1} \cdot(1 \times 2)+{ }^{3} C_{2} \cdot(2 \times 3)+{ }^{4} C_{3} \cdot(3 \times 4)+\ldots+{ }^{19} C_{18} \cdot(18 \times 19)\) is S, then \(\frac{S}{295}\) is equal to

(1) 104

(2) 107

(3) 103

(4) 114 

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1 Answer

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by (43.7k points)

Correct option is: (4) 114  

The sum of series

\(=\frac{18 \times 19 \times 20 \times 21}{4}-\frac{18 \times 19 \times 20}{3}\)

\(=18 \times 19\left[105-\frac{20}{3}\right]==\frac{18 \times 19}{3}[295]=33630\)

\(\frac{S}{295}=6 \times 19=114\)  

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