Question

Calculate the mass of nitrogen present in 1.6 g of following compound

Answer 1

Answer is: 0.52

\(C_4H_{10} N_2 \rightarrow \text{Molar mass }= 12 \times 4 + 1 \times 10 + 14 \times 2\)

\(= 48+10+28\)

\(= 86\)

\(86 \ gm \ o.c \rightarrow 28g \ nitrogen\)

\(1.6 \ gm \ o.c \rightarrow \frac{28}{86} \times 1.6\)

\(= 0.52 \ g\)