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in Chemistry by (22.5k points)
closed ago by

Determine the osmotic pressure of a solution prepared by dissolving 2.32 × 10–2 g of K2SO4 in 2 L of solution at \(25 ^\circ \text{C}\), assuming that K2SO4 is completely dissociated.

(R = 0.082 L atm K–1 mol–1 , Molar mass K2SO4 = 174 g mol–1 )

1 Answer

+1 vote
by (25.7k points)
selected ago by
 
Best answer

Concentration of K2SO4 solution \(= \frac{2.32 \times 10^{-2}}{174 \times 2} = 6.67 \times 10^{-5} \ \text{M}\) 

van’t Hoff factor, i = 3

Osmotic pressure, \(\pi = icRT\)

= 3 × 6.67 × 10–5 × 0.082 × 298

= 4.89 × 10–3 atm

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