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First Bohr orbit of \(H^+\) is radius \(r _0\). Find ground state radius of  \(Li^{+2}\)

(1) \(\frac{r_0}{3}\)

(2) \(4r_0\)

(3) \(2r_0\)

(4) \(3r_0\)

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Correct option is : (1) \(\frac{r_0}{3}\)

\(r \propto \frac{n^2}{z}\)

\(r \propto \frac{1}{z}\)

\(\frac{r_{Li^{2+}}}{r_{H^+}} = \frac{1}{3}\)

\(r_{Li^{2+}} = \frac{r_0}{3}\)

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