Correct option is : (3) \(\frac{49}{25}\)
Voltage sensitivity = \(\frac{NAB}{CR}\)
\(\frac{\chi_1}{\chi_2} = \frac{N_1}{N_2} \times \frac{A_1}{A_2} \times \frac{B_1}{B_2} \times \frac{R_2}{R_1}\)
\( = \frac{21}{15} \times \frac{36}{18} \times \frac{0.25}{0.5} \times \frac{7}{5} = \frac{49}{25}\)