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ago in Chemistry by (20.6k points)

Account for the following :

(i) Ti3+ is coloured whereas Sc3+ is colourless in aqueous solution.

(ii) Cr2+ is a strong reducing agent.

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1 Answer

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ago by (21.2k points)

(i) Ti3+ (3d1) has one unpaired electron in 3d sub-shell.

Sc3+ (3d0) does not have any unpaired electron.

Ti3+ in aqueous solution is coloured due to d-d transition but Sc3+ is colourless.

(ii) Cr2+ (3d4) is a strong reducing agent as it is easily oxidised to Cr3+ (3d3) which has a stable configuration due to half-filled t2g.

\(\underset{t_{2g}^{3}e_{g}^{1}} {Cr^{2+}} \rightarrow \underset{t_{2g}^{3}}{Cr^{3+}} +e\)

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