Question

An aqueous solution of HCl with pH 1.0 is diluted by adding equal volume of water (ignoring dissociation of water). The pH of HCl 14. solution would _________ (Given log2 = 0.3 )

(1) Remains same

(2) Increases to 1

(3) Reduces to 0.5

(4) Increases to 1.3

Answer 1

Correct option is: (4) Increases to 1.3

pH = 1

\([H^+] = 10^{-1}\)

\(\text{New }[H^+] = \frac{10^{-1}}{2} = 5 \times 10^{-2}\)

\(pH = -log(5 \times 10^{-2})\)

\(2 - (1 - 0.3 ) = 1.3\)