Question

Consider the following logic circuit.

The output is Y = 0 when \(:\)

(1) A = 1 and B = 1

(2) A = 0 and B = 1

(3) A = 1 and B = 0

(4) A = 0 and B = 0

Answer 1

Correct option is : (1) A = 1 and B = 1

 

\(Y_1 = A.B,Y_2 = \bar A + B\)

\(Y = \overline{Y_1.Y_2} = \bar Y_1 + \bar Y_2\)

\(Y = \overline{A.B} + \overline{\bar A + B}\)

\(Y = \bar A + \bar B + A.\bar B\)

A	B	Y
0	0	1
1	0	1
0	1	1
1	1	0