The correct decreasing order of spin only magnetic moment values (BM) of Cu^+, Cu^(2+), Cr^(2+) and Cr^(3+) ions is:

Question

The correct decreasing order of spin only magnetic moment values (BM) of \(Cu^+ , Cu^{2+}, Cr^{2+} \ \text{and} \ Cr^{3+}\) ions is:

(1) \(Cu^+ > Cu^{2+} > Cr^{3+} > Cr^{2+}\)

(2) \(Cu^{2+} > Cu^+ > Cr^{2+} > Cr^{3+}\)

(3) \(Cr^{2+}> Cr^{3+}> Cu^{2+} > Cu^+\)

(4) \(Cr^{3+} > Cr^{2+} > Cu^+ > Cu^{2+}\)

Answer 1

Correct option is:  (3) \(Cr^{2+}> Cr^{3+}> Cu^{2+} > Cu^+\)

\(Cu^+ : [Ar] \ 3d^{10}, \text{Spin only magnetic moment = 0 B.M.}\)

\(Cu^{+2} : [Ar]3d^9, \ \text{Spin only magnetic moment }= \sqrt{3} B.M.\)

\(Cr^{+2} : [Ar]3d^4, \ \text{Spin only magnetic moment = }\sqrt{24} B.M.\)

\(Cr^{+3}:[Ar]3d^3, \ \text{Spin only magnetic moment =}\sqrt{15} B.M.\) 

\(\text{Order of }\mu \ : Cr^{+2} > Cr^{+3} > Cu^{+2} > Cu^{+}\)