Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
6.7k views
in Physics by (65.3k points)

In the laboratory, you are given a cylindrical beaker containing a fluid and you are asked to determine the density ρ of the fluid. You are to use a spring of negligible mass and unknown spring constant k attached to a stand. An irregularly shaped object of known mass m and density D (D >> ρ) hangs from the spring. You may also choose from among the following items to complete the task. 

• A metric ruler 

• A stopwatch 

• String

(a) Explain how you could experimentally determine the spring constant k.

(b) The spring-object system is now arranged so that the object (but none of the spring) is immersed in the unknown fluid, as shown. Describe any changes that are observed in the spring-object system and explain why they occur.

(c) Explain how you could experimentally determine the density of the fluid. 

(d) Show explicitly, using equations, how you will use your measurements to calculate the fluid density ρ. Start by identifying any symbols you use in your equations.

Symbol Physical quantity

1 Answer

+1 vote
by (70.6k points)
selected by
 
Best answer

(a) Example 1: Measure the unstretched length of the spring. Hang it with the object at rest and measure the stretched length. Call the difference in these lengths ∆x. Equating the weight of the object and the force exerted by the extended spring gives mg = k∆x from which k can be determined. 

Example 2: Set the hanging mass into oscillation. Determine the period T by timing n oscillations and dividing that time by n. The equation T = 2π√ m / k can then be used to find k. 

(b) The spring is stretched less when the object is at rest in the fluid. The fluid exerts an upward buoyant force on the object. Since the net force on the object is still zero, the spring does not need to exert as much force as before and thus stretches less.

c&d)

(1) Measure the length of the spring when the object is immersed in the liquid, and subtract the unstretched length to determine the amount the spring is stretched. This will allow calculation of the force exerted by the spring on the object. 

(2) The volume of fluid displaced is equal to the volume of the object, which can be determined from the given mass and density of the object. 

(3) The buoyant force on the object is equal to the difference of the object’s weight and the force exerted by the spring. 

(4) The buoyant force also equals the weight of the displaced fluid, which equals the product of the fluid density, displaced volume, and g.

Symbol Quantity
ρ fluid density
object volume = displaced water volume
g acceleration of gravity
m mass of object
x spring stretch in air
xw spring stretch in water

First solving for k in air. mg = kx

Then in the fluid. Fsp = kxw

 Fnet = 0 

Fb = mg – Fsp 

ρVg = mg –kxw 

ρVg = mg – (mg/x) xw solve for ρ.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...