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+1 vote
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in Laws of motion by (151k points)
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A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is

(a) Pm/(M+m)

(b) Pm/(M - m)

(c) P

(d) Pm/(M+m)

1 Answer

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by (87.5k points)
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Best answer
(d) : Acceleration of block (a) = (Force applied)/(Total mass)

or  a = P/(M + m)

Therefore, Force on block

= Mass of block x a = MP/(M + m).

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