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Solve (D2 – 2D + 1)y = ex by method of undetermined coefficients.

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Here yC.F. = c1ex + c2xex Since the right hand member of the complete equation is X(x) = ex, therefore the first possible assumption for particular integral would be yP.I. = Aex, but this solution has already occurred in yC.F. We, therefore, yP.I.(x) = Axex. Still this solution also has appeared in yC.F. We, therefore, again multiply by x and try yP.I.(x) = Ax2ex.

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