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The radius of a nucleus is given by r0 A1/3 where r0 = 1.3 × 10-15 m and A is the mass number of the nucleus, the Lead nucleus has A = 206. the electrostatic force between two protons in this nucleus is approximately 

(A) 102

(B) 107

(C) 1012

(D) 1017

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Best answer

Correct Option :- (A) 102 N

Explanation :-

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