For mirror M1: u = -30 cm, f = -20 cm By mirror formula, (1/u) + (1/v) = (1/f), we have
(1/-30) + (1/v) = (1/-30)
which on solving gives, v = -60 cm
For mirror M2: The image formed by mirror M1 is a virtual object for mirror M2. Let it is a distance x from the pole of mirror M2.
Thus u2 = +x, v2 = - (30-x)
Again by mirror formula. We have
(1/x) + (1/-(30-x)) = (1/20)
which on solving gives
x = 10 cm or 60 cm, x = 60 cm is not possible, thus x = 10 cm.
(a) Thus the separation between the mirrors = 60-10= 50 cm
(b) The image formed by mirror M2 is at a distance 10 cm
