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A converging mirror M1, a point source S and a diverging mirror M2 are arranged as shown in the figure. The source is placed at a distance of 30 cm from M1. The focal length of each of the mirror is 20 cm. Consider only the images formed by a maximum of two reflections. It is found that one image is formed on the source itself. 

(a) Find the distance between the mirrors 

(b) Find the location of the image formed by the single reflection from M2.

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For mirror M1: u = -30 cm, f = -20 cm By mirror formula, (1/u) + (1/v) = (1/f), we have

(1/-30) + (1/v) = (1/-30) 

which on solving gives, v = -60 cm 

For mirror M2: The image formed by mirror M1 is a virtual object for mirror M2. Let it is a distance x from the pole of mirror M2.

 Thus u2 = +x, v2 = - (30-x) 

Again by mirror formula. We have 

(1/x) + (1/-(30-x)) = (1/20) 

which on solving gives 

x = 10 cm or 60 cm, x = 60 cm is not possible, thus x = 10 cm. 

(a) Thus the separation between the mirrors = 60-10= 50 cm 

(b) The image formed by mirror M2 is at a distance 10 cm

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