Correct Option :- (a) sin-1 tan i
Explanation :-
The situation in accordance with given problem is shown in figure applying Snell’s law at the boundary at c.
μD sin i = μr sin r’ r’+ r =90
μD sin i = μr sin (90-r)
(incident < reflected & refracted reflected ray & refracted ray are ﬩ to from reflection each other r’+ r =90)
μD sin i = μr cos r but i=r
μD sin i = μr cos i
μD /μr =cos i/ sin i = cot i
1/μ = tan i
but by definition θc =sin-1(1/μ) ⇒ θc =sin-1(1/μ)
θc =sin-1(tan i)