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Water coming out of a horizontal tube at a speed v strikes normally a vertically wall close to the mouth of the tube and falls down vertically after impact. When is the speed of water increased to 2v. 

(A) the thrust exerted by the water on the wall will be doubled. 

(B) the thrust exerted by the water on the wall will be four times 

(C) the energy lost per second by water striking the wall will also be four times 

(D) the energy lost per second by water striking the wall be increased eight times. 

1 Answer

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Best answer

Correct Option (B,D)

Explanation:

 Thrust exerted by the water is ρAV2 if velocity is doubled then thrust will increase 4 times.

Energy lost per second

If velocity is doubled then energy lost per second will be 8 times

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