Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
32.8k views
in Physics by (14.7k points)

The radius of gyration of a uniform disc about a line perpendicular to the disc equals its radius. Find the distance of the line from the centre.

1 Answer

0 votes
by (323k points)
selected by
 
Best answer

The moment of inertia about the center and ⊥ to the plane of the disc of
radius r and mass m is = mr2.
According to the question the radius of gyration of the disc about a point = radius of the disc.
Therefore mk2 = ½ mr2 + md2
(K = radius of gyration about acceleration point, d = distance of that point from the centre)
 K2 = r2/2 + d2
 r2 = r2/2 + d2 (K = r)
 r2/2 = d2 = d = r / 2 .

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...