Question

In a upper triangular matrix n×n, minimum number of zeros is 

(a)  n(n – 1)/2

(b)  n(n + 1)/2

(c)  2n(n – 1)/2 

(d)  None of these

Answer 1

Correct option (a) n(n – 1)/2

Explanation:

As we know, a square matrix A = | a_ij | is called an upper triangular matrix if a_ij = 0 for all i > j.

Hence number of zeros in a upper triangular matrix of

order n x n = n(n - 1)/2