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If sin2x + sinx = 1, then cos12x + 3cos10 x + 3cos8x + cos6x – 1 is equal to 

(A) 1 

(B) 0 

(C) –1 

(D) none of these 

1 Answer

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Best answer

Correct option (B) 0

Explanation:

sin2x + sin x = 1  sin x = cos2 x cos12 x + 3 cos10 x + 3 cos8 x + cos6 x – 1 = (sin6 x) + 3 sin5 x + 3 sin4 x + (sin3 x) – 1 

= (sin2 x)3 + 3(sin2 x)2 sin x + 3sin2 x sin2 x + (sin x)3 – 1 = (sin2 x + sin x)3 – 1 = 1 – 1 = 0

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