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Let x, y be real variable satisfying the x^2 + y^2 + 8x – 10y – 40 = 0. Let a = max {(x + 2)^2 + (y – 3)^2}

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Let x, y be real variable satisfying the x2 + y2 + 8x – 10y – 40 = 0. Let a = max {(x + 2)2 + (y – 3)2} and b = min {(x + 2)2 + (y – 3)2}, then

(A) a + b = 18 

(B) a + b = 4√2 

(C) a – b = 4√2 

(D) a. b = 73

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Correct option (A) (C) (D)

Explanation:

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