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Let a1 , a2 , ..., a10 be in A.P., h1 , h2 , ..., h10 be in H.P. If a1 = h1 = 3, a10 = h10 = 6, then a7 h4 is

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Let a1 , a2 , ..., a10 be in A.P., h1 , h2 , ..., h10 be in H.P. If a1 = h1 = 3, a10 = h10 = 6, then a7 h4 is

(1) 18 

(2) 5 

(3) 5/18 

(4) 18/25

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1 Answer

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Best answer

Correct option (1) 18

Explanation: 

a10 = 6 ⇒ a1 + 9d = 6, where d is

the common difference of the A.

⇒ 9d = 6 − 3 = 3 

where D is the common difference of the A.P.

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