Correct option (B) 1/9
Explanation:
For interference at A : S2 is behind of S1 by a distance of 100 + λ/4 .(equal to phase difference π/2).
Further S2 lags S1 by π/2 . Hence the waves from S1 and S2 interfere at A with a phase difference of 200.5π + 0.5π = 201π = π
Hence the net amplitude at A is 2a – a = a
For interference at B : S2 is ahead of S1 by a distance of 100λ + λ/4 .(equal to phase difference π/2).
Further S2 lags S1 by π/2.
Hence waves from S1 and S2 interfere at B with a phase difference of 200.5π – 0.5π = 200π = 0π.
Hence the net amplitude at A is 2a + a = 3a
Hence (IA/IB) = (a/3a)2 = 1/9