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9.4k views
in Physics by (71.8k points)

'Identical dielectric slabs are inserted into two identical capacitors A and B. These capacitors and a battery are connected as shown in figure. Now the slab of capacitor B is pulled out with battery remaining connected :

(A) During the process positive charge flows from a to b. 

(B) Finally charge on capacitor B will be less than that on capacitor A. 

(C) During the process, a work is done by the external force F, which completely appears as heat in the circuit. 

(D) During the process, internal energy of the battery increases.

1 Answer

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by (79.9k points)
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Best answer

Correct option (A) During the process positive charge flows from a to b

Explanation:

(A) Charge on capacitor B decreases as dielectric slab is taken out. Charge from positive plate of B flows towards battery. Charge on A and B can not be different, as being connected in series. During the process, battery is being charged. 

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