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Orthogonal trajectories of family of parabolas y^2 = 4a(x + a) where ‘a’ is an arbitrary constant is

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Orthogonal trajectories of family of parabolas y2 = 4a(x + a) where ‘a’ is an arbitrary constant is 

(a) ax2 = 4cy

(b) x2 + y2 = a2 

(c) y ce(-x/2a)

(d) axy = c2, where c is a constant

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Correct option (c)

Explanation:

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