Question

The Boolean representation of a logic gate circuit using two inputs A and B having output C is

C = bar (A.B).(A+B)

The correct circuit is:

Answer 1

Correct option: (3)

Explanation: 

Let C₁ = A.B and C₂ = A +B. C₁ is output of a AND gate using A and bar B as inputs. C₂ is output of a OR gate using bar A and B as input. C₁ and C₂ are inputs of a NAND gate. This is shown correctly in (3).