Correct option: (3)
Explanation:
We know that
λ/4 = first resonance length + end correction
and 3λ/4 = second resonance length + end correction
Also end correction = 0.3 (Diameter of the tube). As the students are working in the same laboratory (hence same value of velocity of sound) and are using tuning forks of same frequency, the value of λ must be the same in both cases (λ = V/N). We, therefore, have
