
m = mass per unit length of the string
R = Radius of the loop
ω= angular velocity, V = linear velocity of the string
Consider one half of the string as shown infigure.
The half loop experiences centrifugal force at every point, away from centre, which is balanced by tension 2T.
Consider an element of angular part dθ at angle θ. Consider another element symmetric to this centrifugal force experienced by the element
= (mRdθ)ω2R.
(…Length of element = Rdθ, mass = mRdθ)
Resolving into rectangular components net force on the two symmetric elements,
