The reaction, 2AB(g) + 2C(g)→ A2(g) + 2BC(g), proceeds according to the mechanism :
(I) 2AB ⇋ A2B2 (fast)
(II) A2B2 + C → A2B + BC (slow)
(III) A2B + C → A2 + BC (fast)
What will be the initial rate taking [AB] = 0.2 M and [C] = 0.5 M? The Kc for the step I is 102 M–1 and rate constant for the step II is 3.0 × 10–3 mol–1 L min–1.
(a) 0.0716 M min–1
(b) 0.0891 M min–1
(c) 0.006 M min–1
(d) 0.0257 M min–1
