Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
8.4k views
in Chemistry by (71.2k points)

The solubility of Mg(OH)2 is increased by addition of NH4+ ion. Find 

(i) Kc for the reaction

Mg(OH)2 + 2NH4+ ⇌ 2NH3 + 2H2O + Mg2+ 

(ii) Calculate solubility of Mg(OH)2 in a solution containing 0.5 M NH4Cl

(Ksp [Mg(OH)2] = 1.0 × 10–11, Kb(NH3) = 1.8 × 10–5)

1 Answer

+1 vote
by (63.7k points)
selected by
 
Best answer

(i) For the reaction

(ii) Now, let us, assume that 'a' moles of Mg(OH)2 be dissolved in presence of 0.5 M NH4Cl.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...