Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
704 views
in Chemistry by (71.2k points)

Describe the titration of strong acid against strong alkali.

1 Answer

+1 vote
by (63.7k points)
selected by
 
Best answer

The graph (A) shows how pH changes during the titration of 50 cm3 of 0.1 M HCl with 0.1 M NaOH. 

NaOH (aq) + HCl (aq) → NaCl (aq) + H2O (l) 

The pH of 0.1 M solution of HCl in the beginning would be 1. As alkali is added, the pH changes slowly in the beginning. However, at the equivalence point pH changes rapidly from about 3.5 to 10. It can be shown by simple calculations that pH of the solution is 3.7 when 49.8 cm3 of 0.1 M NaOH solution have been added. The pH suddenly changes to 10 after addition of 50.1 cm3 of the NaOH solution. Thus, any indicator having pH range between 3.5 to 10 will identify the equivalence point. This means that any one of phenolphthalein, methyl orange or bromothylmol blue could be used as an indicator.

Titration curves : (A) strong base with strong acid ; 

(B) weak base with strong acid ; 

(C) strong base with weak acid ; 

 (D) weak base with weak acid.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...