Question

A square loop of side 1m is placed in a perpendicular magnetic field. Half of the area of the loop lies inside the magnetic field. A battery of emf 10V and negligible internal resistance is connected in the loop. The magnetic field change with time according to the relation B = (0.01 –2t) tesla. The total emf of the battery will be - 

(A) 11V 

(B) 9 V 

(C) 12 V 

(D) 6 V  

Answer 1

Correct option (B) 9 V

Explanation:

emf induced is, 

∴ Resultant emf = 10 – 1 = 9V