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Find the least number which when divided by 6,7,8, 9, and 12 leave the same remainder 1 each case.

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Find the least number which when divided by 6,7,8, 9, and 12 leave the same remainder 1 each case.

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Required number = (L.C.M OF 6,7,8,9,12) + 1

L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.

Hence required number = (504 +1) = 505.

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